2[k-(2k+12)+8]=2(k+4)

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Solution for 2[k-(2k+12)+8]=2(k+4) equation:


Simplifying
2[k + -1(2k + 12) + 8] = 2(k + 4)

Reorder the terms:
2[k + -1(12 + 2k) + 8] = 2(k + 4)
2[k + (12 * -1 + 2k * -1) + 8] = 2(k + 4)
2[k + (-12 + -2k) + 8] = 2(k + 4)

Reorder the terms:
2[-12 + 8 + k + -2k] = 2(k + 4)

Combine like terms: -12 + 8 = -4
2[-4 + k + -2k] = 2(k + 4)

Combine like terms: k + -2k = -1k
2[-4 + -1k] = 2(k + 4)
[-4 * 2 + -1k * 2] = 2(k + 4)
[-8 + -2k] = 2(k + 4)

Reorder the terms:
-8 + -2k = 2(4 + k)
-8 + -2k = (4 * 2 + k * 2)
-8 + -2k = (8 + 2k)

Solving
-8 + -2k = 8 + 2k

Solving for variable 'k'.

Move all terms containing k to the left, all other terms to the right.

Add '-2k' to each side of the equation.
-8 + -2k + -2k = 8 + 2k + -2k

Combine like terms: -2k + -2k = -4k
-8 + -4k = 8 + 2k + -2k

Combine like terms: 2k + -2k = 0
-8 + -4k = 8 + 0
-8 + -4k = 8

Add '8' to each side of the equation.
-8 + 8 + -4k = 8 + 8

Combine like terms: -8 + 8 = 0
0 + -4k = 8 + 8
-4k = 8 + 8

Combine like terms: 8 + 8 = 16
-4k = 16

Divide each side by '-4'.
k = -4

Simplifying
k = -4

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